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Question

If the vectors^3i=^4j^2k, ^i+^2k, ^i^pj are coplanar then the value of p is ?

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Solution

Given that the vector 3ˆi+4ˆj2ˆk,ˆi+2ˆk,ˆipˆj are coplaner

so
[3ˆi+4ˆj2ˆk,ˆi+2ˆk,ˆipˆj]=0

(3ˆi+4ˆj2ˆk)∣ ∣ ∣ˆi ˆj ˆk1021p0∣ ∣ ∣=0

(3ˆi+4ˆj2ˆk)(2pˆi+2ˆj2p)=0

6p+8+2p=0
8=4p
p=2






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