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Question

If the vectors ^i2^j+^k,2^i5^j+p^k and are 5^i9^j+4^k are coplanar, then find the value of p

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Solution

We know that if 3 vectors a,vecb,c are co-planar, then [a,b,c]=0
12125p594=0
1(20+9p)+2(85p)+1(18+25)=0
9p20+1610p+7=0
3p=0
p=3

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