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Question

If the vectors a,b,c from the sides BC,CA,AB respectively of triangle ABC, then

A
a.b+b.c+c.a=0
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B
a×b=b×c=c×a
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C
a.b=b.c=c.a
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D
a×b+b×c+c×a=0
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Solution

The correct option is C a×b=b×c=c×a
Given: a+b+c=0
a×(a+b+c)
=a×a+a×b+a×c=0
But a×a=0
a×b+a×c=0
a×b=a×c
a×b=c×a
b×(a+b+c)
b×a+b×b+b×c=0
But b×b=0 b×c=a×b
a×b=c×a
a×b=b×c=c×a

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