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Question

If the vectors x^i+^j+^k,^i+y^j+^k and ^i+^j+z^k are co-planar where x1,y1,z1, then prove that 11x+11y+11z=1.

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Solution

Since,
Three given vectors are coplanar,

Then,

∣ ∣x111y111z∣ ∣=0x(yz1)1(z1)+1(1y)=0xyzxyz+2=0(1)

Now,

11x+11y+11z=(1y)(1z)+(1x)(1z)+(1x)(1y)(1x)(1y)(1z)=1zy+yz+1zx+zx+1yx+xy(1x)(1zy+yz)=xy+yz+zx2(x+y+z)+31zy+yzx+zx+xyxyz=32(x+y+z)+xy+yz+zx1(xyz)xyz+xy+yz+zx=32(x+y+z)+xy+yz+zx1(x+y+z)xyz+xy+yz+zxfrom(1)=32(x+y+z)+xy+yz+zx3(x+y+z)xyz+xy+yz+zx=32(x+y+z)+xy+yz+zx32(x+y+z)+xy+yz+zx=1

Hence, proved.

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