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Byju's Answer
Standard XII
Physics
Momentum
If the veloci...
Question
If the velocity of a body is increased
4
% then what is the approximate % change in its K.E.?
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Solution
Let m= mass of the object and v= velocity of the object ,so kinetic energy of the object
E
K
.
I
=
1
2
m
v
2
------------(1)
Now as mentioned in the question velocity increased by 4%, thus kinetic energy of the object
E
K
F
=
1
2
m
(
0.04
v
)
2
-----(2)
Now comparing 1 and 2 we get,
Change in kinetic energy
Δ
E
K
=
1
2
m
(
v
2
−
0.0016
v
2
)
Δ
E
K
=
49.92
m
%
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