If the velocity of a moving car is reduced to half its original velocity, its kinetic energy would
The correct option is
D
Become one fourth
v′=v2
KE′=12m(v′)2
KE′=12m(v2)2
KE′=18mv2=KE4
Kinetic energy is directly proportional to velocity squared (K.E. = 12mv2). So, if velocity is halved, then kinetic energy becomes one fourth.