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Question

If the velocity of a particle depends upon time as v(t)=(10+2t3)m/s, then the average acceleration of the particle between the times 2s and 5s is


A

87m/s2

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B

260m/s2

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C

26m/s2

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D

78m/s2

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Solution

The correct option is D

78m/s2


Average acceleration = change in velocitytime taken

= v2v1t2t1

= [10+2(5)3][10+2(2)3]3=260263=2343=78m/s2


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