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Standard XII

Physics

COM in Oblique Collision

If the veloci...

Question

If the velocity of centre of mass of a rolling body is $V$ then velocity of highest point of that body is :

\sqrt{2} V

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V

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2 V

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\frac{V}{\sqrt{2}}

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Solution

The correct option is D $2 V$
$u = r ω$
As the body is rolling, so velocity of point B must be zero.
$V_{B} = V - u = 0 ⟹ V = u = r ω$
Now velocity of point A, $V_{A} = V + u = V + V = 2 V$

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If the velocity of centre of mass of a rolling body is V then velocity of highest point of that body is :

The correct option is D 2Vu=rωAs the body is rolling, so velocity of point B must be zero.VB=V−u=0⟹V=u=rωNow velocity of point A, VA=V+u=V+V=2V

If the velocity of centre of mass of a rolling body is $V$ then velocity of highest point of that body is :

The correct option is D $2 V$
$u = r ω$
As the body is rolling, so velocity of point B must be zero.
$V_{B} = V - u = 0 ⟹ V = u = r ω$
Now velocity of point A, $V_{A} = V + u = V + V = 2 V$