If the velocity of sound in a gas is 360 m/s and the distance between compression and the nearest rarefraction is 1m, then the frequency of sound is

90 Hz

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180 Hz

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360 Hz

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720 Hz

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Solution

The correct option is B 180 Hz
Given,
$v = 360 m / s$
$\frac{λ}{2} = 1 m$
$λ = 2 m$
frequency, $f = \frac{v}{λ}$
$f = \frac{360}{2} = 180 H z$
The correct option is B.

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