If the velocity of sound in air is 350 m/s. Then the fundamental frequency of an open organ pipe of length 50 cm, will be

350 Hz

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175 Hz

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900 Hz

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750 Hz

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Solution

The correct option is A
350 Hz

Fundamental frequency of open pipe

$n_{1} = \frac{v}{2 l} = \frac{350}{2 \times 0.5} = 350$ Hz.

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350 m / s

50 c m

350 m s^{- 1}

50

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v

^{- 1}

m s^{- 1}

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