If the velocity of water near the surface of a $6$ m deep river is $6$ m $/$ s, assuming uniform velocity gradient along the depth, find the shear stress between the horizontal layers of water (coefficient of viscosity of water $= 10^{- 2}$ poise).

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Solution

Shear stress = $- μ \frac{d u}{d y}$
= $10^{- 2} \times \frac{6}{6}$
= $- 10^{- 2} \frac{p o i s e}{s e c .}$

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If the velocity of water near the surface of a 6m deep river is 6 m/s, assuming uniform velocity gradient along the depth, find the shear stress between the horizontal layers of water (coefficient of viscosity of water =10−2 poise).

Shear stress = −μdudy = 10−2×66 = −10−2poisesec.

If the velocity of water near the surface of a $6$ m deep river is $6$ m $/$ s, assuming uniform velocity gradient along the depth, find the shear stress between the horizontal layers of water (coefficient of viscosity of water $= 10^{- 2}$ poise).

Shear stress = $- μ \frac{d u}{d y}$
= $10^{- 2} \times \frac{6}{6}$
= $- 10^{- 2} \frac{p o i s e}{s e c .}$