If the vertex $= (2, 0)$ and the extremities of the latus rectum are $(3, 2)$ and $(3, - 2)$ , then the equation of the parabola is

y^{2} = 2 x - 4

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x^{2} = 4 y - 8

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y^{2} = 4 x - 8

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Solution

The correct option is D $y^{2} = 4 x - 8$
$y^{2} = 4 a x$

$(y - 0)^{2} = 4 a (x - 2)$

$y^{2} = 4 a (x - 2)$

$y^{2} = 4 (x - 2)$

$y^{2} = 4 x - 8$

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Similar questions

(2, 0)

(3, 2)

(3, - 2)

Latus rectum of the parabola $y^{2} - 4 y - 2 x - 8 = 0$ is

y^{2} = 4 x + 4 y .

y^{2} + 4 x + 4 y - 3 = 0

y^{2} - 4 x + 4 y + 8 = 0

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