If the vertex of a parabola is $(2, 0)$ and the extremities of the latus rectum are $(3, 2)$ and $(3, - 2)$ then the equation of the parabola is

y^{2} = 2 x - 4

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x^{2} = 4 y - 8

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y^{2} = 4 x - 8

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none of these

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Solution

The correct option is D $y^{2} = 4 x - 8$
Focus is the midpoint of latus rectum.
Coordinates of focus are $(3, 0)$
Vertex is $(2, 0)$
From the standard form of the parabola we have,
$y^{2} = 4 (x - 2)$

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Similar questions

= (2, 0)

(3, 2)

(3, - 2)

Latus rectum of the parabola $y^{2} - 4 y - 2 x - 8 = 0$ is

y^{2} = 4 x + 4 y .

y^{2} - 4 x + 4 y + 8 = 0

y^{2} + 4 x + 4 y - 3 = 0

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