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Standard XII

Mathematics

Vertex

If the vertex...

Question

If the vertex of parabola y = $x^{2}$ -8x + c lies on x - axis, then the value of c is

-16

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Solution

The correct option is D
16

The given equation can be written as $(x - 4)^{2} = y - (c - 16)$ . Therefore the vertex of the parabola is (4, c – 16). The point lies on x – axis.

$∴ c - 16 = 0 \Rightarrow c = 16$

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If the vertex of parabola y = x2-8x + c lies on x - axis, then the value of c is

The correct option is D 16 The given equation can be written as (x−4)2=y−(c−16). Therefore the vertex of the parabola is (4, c – 16). The point lies on x – axis. ∴ c−16=0⇒c=16

If the vertex of parabola y = $x^{2}$ -8x + c lies on x - axis, then the value of c is

The correct option is D
16

The given equation can be written as $(x - 4)^{2} = y - (c - 16)$ . Therefore the vertex of the parabola is (4, c – 16). The point lies on x – axis.

$∴ c - 16 = 0 \Rightarrow c = 16$