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Vertex

If the vertex...

Question

If the vertex of parabola y = $x^{2}$ -8x + c lies on x - axis, then the value of c is

-16

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-4

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Solution

The correct option is D
16

The given equation can be written as $(x - 4)^{2} = y - (c - 16)$ . Therefore the vertex of the parabola is (4, c – 16). The point lies on x – axis.

$∴ c - 16 = 0 \Rightarrow c = 16$

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Similar questions

If the vertex of parabola y = $x^{2}$ -8x + c lies on x - axis, then the value of c is

O A B C

O

A

C

y = x^{2}

B

(α, β)

α + β

O A B C

O

A

C

y = x^{2}

B

(α, β)

α + β

x + y - 1 = c

x^{2} + y - x = 0,

c

y^{2} = 4 a x

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