If the vertex of the parabola y-x2-16 x-k lies on x -axis- then k-

Given parabola is, nbsp; y = x2 nbsp; minus; 16x + k nbsp; nbsp; nbsp;= x2 nbsp; minus; 2x(8) + k nbsp; nbsp; nbsp; nbsp;= x2 nbsp; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Plotting a Point

If the vertex...

Question

If the vertex of the parabola y = x² – 16x + k lies on x-axis, then k = __________.

Open in App

Solution

Suggest Corrections

Similar questions

(k, k^{2})

y^{2} = 64 x

- x^{2} + x - 1 + y = 0

k

(k, k^{2})

y^{2} = 64 x

- x^{2} + x - 1 + y = 0

k

f (x) = x^{2} + (3 - k) x + k, (w h e r e k \in R)

x - a x i s

k

(k, k + 2)

x^{2} = 4 (y + 2)

x^{2} = - (y - 4)

k

2 x + y + k = 0

y^{2} = - 16 x

k

Join BYJU'S Learning Program