If the vertices of a -PQR are P1- 2- Q3- -4 and R5- -6- then its centroid is

Vertices of ΔPQR are P(1, 2), Q(3, –4) and R(5, –6). Centroid of ΔPQR nbsp;=1+3+53,2 4 63 nbsp; nbsp; nbsp;=3, 83 Hence, the correct answer is opt ...

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If the vertic...

Question

If the vertices of a ΔPQR are P(1, 2), Q(3, –4) and R(5, –6), then its centroid is

(-7, 4)

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(9, 3)

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(3, - \frac{8}{3})

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(- 8, \frac{11}{3})

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Solution

The correct option is C $(3, - \frac{8}{3})$
Vertices of ΔPQR are P(1, 2), Q(3, –4) and R(5, –6).

Centroid of ΔPQR $= \frac{1 + 3 + 5}{3}, \frac{2 - 4 - 6}{3}$

$= 3, \frac{- 8}{3}$

Hence, the correct answer is option (c).

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If the vertices of a ΔPQR are P(1, 2), Q(3, –4) and R(5, –6), then its centroid is

The correct option is C (3,−83)Vertices of ΔPQR are P(1, 2), Q(3, –4) and R(5, –6). Centroid of ΔPQR =1+3+53,2−4−63 =3,−83 Hence, the correct answer is option (c).

The correct option is C $(3, - \frac{8}{3})$
Vertices of ΔPQR are P(1, 2), Q(3, –4) and R(5, –6).

Centroid of ΔPQR $= \frac{1 + 3 + 5}{3}, \frac{2 - 4 - 6}{3}$

$= 3, \frac{- 8}{3}$

Hence, the correct answer is option (c).