If the vertices of a triangle are $(1, - 1), (- 4, 6), (- 3, - 5)$ then the area of triangle is :

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Solution

$\begin{matrix} L e t t h e t w o p o i n t s b e A (1, - 1), B (- 4, 6) a n d c (- 3, - 5) N o w, A r e a o f t r i a n g l e A B C = \frac{1}{2} [x_{1} (y_{2} - y_{3}) + x_{2} (y_{3} - y_{1}) + x_{3} (y_{1} - y_{2})] = \frac{1}{2} [1 (6 + 5) - 4 (- 5 + 1) - 3 (- 1 - 6)] = \frac{1}{2} [11 + 16 + 21] = \frac{1}{2} [58] = \frac{58}{2} = 29 s q . u n i t s \end{matrix}$

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