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Question

If the vertices of a triangle are the points with position vectors a1i^+a2j^+a3k^, b1i^+b2j^+b3k^, c1i^+c2j^+c3k^, what are the vectors determined by its sides? Find the length of these vectors.

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Solution

Given the vertices of a triangle A, B and C with position vectors a1i^ + a2j^ + a3k^, b1i^+b2j^+b3k^ and c1i^+c2j^+c3k^ respectively. Then,
AB = (b1-a1)i^ + (b2-a2) j^ + (b3-a3)k^.BC = (c1-b1)i^ + (c2-b2) j^ + (b3-a3)k^.CA = (a1-c1)i^ + (a2-c2) j^ + (a3-c3) k^.
Therefore, the length of these vectors are:

AB = (b1-a1)2+ (b2-a2)2+ (b3-a3)2 .BC = (c1-b1)2+(c2-b2)2+(c3-b3)2.CA = (a1-c1)2+ (a2-c2)2 + (a3-c3)2.

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