If the vertices of a triangle be (0,0), (6,0) and (6,8), then its incentre will be
(2,1)
(1,2)
(4,2)
(2,4)
Let A(0 , 0), B(6, 0) and C(6, 8)
Thus c = AB = 6, a = BC = 8 and b = AC = 10
Hence incentre
= (8×0+10×6+6×68+10+6,8×0+10×0+6×88+10+6) = (4, 2).
Write the coordinates of the incentre of the triangle having its vertices at(0,0),(5,0) and (0,12).