Question

If the vertices of a triangle be (0,0), (6,0) and (6,8), then its incentre will be

• A. (2,1)
• B. (1,2)
• C. (4,2)
• D. (2,4)

Answer 1

The correct option is C

(4,2)

Let A(0 , 0), B(6, 0) and C(6, 8)

Thus c = AB = 6, a = BC = 8 and b = AC = 10

Hence incentre

= $(\frac{8\times 0+10\times 6+6\times 6}{8+10+6},\frac{8\times 0+10\times 0+6\times 8}{8+10+6})$ = (4, 2).