If the vertices of a triangle be (a, b - c), (b, c - a) and (c, a - b), then the centroid of the triangle lies

At origin

No worries! We‘ve got your back. Try BYJU‘S free classes today!

On x-axis

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

On y-axis

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
On x-axis

x = $\frac{a + b + c}{3}$ , y = $\frac{b - c + c - a + a - b}{3}$ = 0

Hence, centroid lies on x - axis.

Suggest Corrections

Similar questions

(a, 1, 3)

(- 2, b, - 5)

(4, 7, c)

a, b, c

(c^{2}, - 3)

\vec{a}, \vec{b}, \vec{c}

\vec{a} + \vec{b} + \vec{c}

Join BYJU'S Learning Program