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Question

If the vertices of the ABC are A(3,0),B(4,1) and C(5,2), then the length of the altitude from A to BC is

A
157 units
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B
810 units
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C
2210 units
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D
227 units
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Solution

The correct option is C 2210 units
Given vertices are A(3,0),B(4,1) and C(5,2)
We know that the are of the triangle is
Δ=12x1x2x3x1y1y2y3y1Δ=1234530120Δ=12|(30)+(8+5)+(0+6)|Δ=12|22|=11
Now, we know that,
Δ=12×AD×BC11=12×AD×(45)2+(12)2
AD=2210 units

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