If the vertices of the △ABC are A(−3,0),B(4,−1) and C(5,2), then the length of the altitude from A to BC is
A
15√7 units
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B
8√10 units
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C
22√10 units
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D
22√7 units
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Solution
The correct option is C22√10 units Given vertices are A(−3,0),B(4,−1) and C(5,2) We know that the are of the triangle is Δ=12∣∣∣x1x2x3x1y1y2y3y1∣∣∣⇒Δ=12∣∣∣−345−30−120∣∣∣⇒Δ=12|(3−0)+(8+5)+(0+6)|⇒Δ=12|22|=11 Now, we know that, Δ=12×AD×BC⇒11=12×AD×√(4−5)2+(−1−2)2 ∴AD=22√10 units