If the vertices of triangle are (0,2), (1,0) and (3,1), then the triangle is

Equilateral

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Isosceles

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Right angled

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Isosceles right angled

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Solution

The correct option is D
Isosceles right angled

Here A(0, 2), B(1, 0) and C(3, 1).

Therefore, AB = $\sqrt{1 + 4}$ = $\sqrt{5}$ , BC = $\sqrt{4 + 1}$ = $\sqrt{5}$

and AC = $\sqrt{9 + 1}$ = $\sqrt{10}$

It is clear that $(A C)^{2}$ = $(A B)^{2}$ + $(B C)^{2}$

Hence, triangle is isosceles right angled.

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