Question

If the vertices of triangle are (0,2), (1,0) and (3,1), then the triangle is

• A. Equilateral
• B. Isosceles
• C. Right angled
• D. Isosceles right angled

Answer 1

The correct option is D

Isosceles right angled

Here A(0, 2), B(1, 0) and C(3, 1).

Therefore, AB =$\sqrt{1+4}$ = $\sqrt{5}$, BC = $\sqrt{4+1}$ = $\sqrt{5}$

and AC = $\sqrt{9+1}$ = $\sqrt{10}$

It is clear that $(AC{)}^2$ = $(AB{)}^2$ + $(BC{)}^2$

Hence, triangle is isosceles right angled.