Question

If the voltage of a source in an AC circuit is represented by the equation, $E=220\sqrt{2}\sin \left(314t\right)$. The frequency of the voltage is -

Take $\pi =3.14$

• A. $100\text{Hz}$
• B. $50\text{Hz}$
• C. $200\text{Hz}$
• D. $150\text{Hz}$

Answer 1

The correct option is B $50\text{Hz}$

Given:

Voltage, $E=220\sqrt{2}\sin \left(314t\right)$

Comparing with $E=E_0\sin \omega t$, we get, angular frequency,

$\omega =314\text{rad/s}$

So, frequency, $f=\frac{\omega }{2\pi }=\frac{314}{2\times 3.14}=50\text{Hz}$