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Stress-Strain Graph

If the volume...

Question

If the volume density of the elastic deformation energy in fresh water at the depth of $h = 1000 m$ is $x K J / m^{3}$ , find the value of $\frac{x}{5}$ .(rounded off to nearest integer)

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Solution

Energy density is given by $\frac{1}{2} \times S t r e s s \times S t r a i n$ .
Stress is the pressure, $ρ g h$ ,
Strain $= β ρ g h$ , by the definition of $β$ .
Thus, $u = \frac{1}{2} β {(ρ g h)}^{2} = 23.5 k J / m^{3}$
Thus, $2 x = 47$

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