Question

If the volume occupied in a crystal by a molecule of NaCl is $47\times {10}^{-24}mL$, calculate the volume of the crystal weighing 1 g.

• A. $0.34mL$
• B. $0.484mL$
• C. $0.22mL$
• D. $0.584mL$

Answer 1

Answer: (B)

$0.484mL$

1 molecule of NaCl weighs =$\frac{58.5}{6.02\times {10}^{23}}$g

1 molecule occupies = 47 x 10${}^{-24}$ mL

Volume occupied by 1q = $\frac{47{\times }^{-24}\times 6.02\times {10}^{23}}{58.5}$ =0.484 mL