Question

If the volume of a cube is $3\sqrt{3}{a}^3$ then total surface area of the cube is

• A. $6a^2$
• B. $\sqrt{3}{a}^2$
• C. $18a^2$
• D. none of these

Answer 1

The correct option is C $18a^2$

Volume of the cube=$a^3$

Given volume of the cube$=3\sqrt{3}{a}^3$

$\therefore a^3=3\sqrt{3}{a}^3$

$\Rightarrow a=\sqrt{3}a$

Total surface area of the cube=$6a^2$

$\Rightarrow 6(\sqrt{3}a{)}^2$

$\Rightarrow 6\times 3a^2=18a^2$