If the volume of a given mass of a gas at constant temperature becomes three times, the pressure will be:

3 p

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p / 3

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9 p

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p

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Solution

The correct option is B $p / 3$
According to the ideal gas equation,

$P V = n R T$

$P_{1} V_{1}$ = $P_{2} V_{2}$

Hence volume becomes 3 times, the pressure will be $\frac{p}{3}$

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If the volume of a given mass of a gas at constant temperature becomes three times, the pressure will be:

The correct option is B p/3According to the ideal gas equation,PV=nRTP1V1=P2V2Hence volume becomes 3 times, the pressure will be p3

The correct option is B $p / 3$
According to the ideal gas equation,

$P V = n R T$

$P_{1} V_{1}$ = $P_{2} V_{2}$

Hence volume becomes 3 times, the pressure will be $\frac{p}{3}$