If the volume of a room is $792 m^{3}$ and the area of the floor is $132 m^{2}$ , find the height of the room.

8 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Data insufficient

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $6$ m
Volume of the room $(l \times b \times h) = 792 m^{3}$

Area of the floor $(l \times b)$ $= 132 m^{3}$

Therefore, height of the room $= \frac{v o l u m e o f t h e r o o m}{a r e a o f t h e f l o o r}$

$= \frac{792 m^{3}}{132 m^{2}} = 6 m$

Suggest Corrections

Similar questions

660 m^{3}

132 m^{2}

660 m^{3}

132 m^{2}

67.5 s q . m .

270 m^{3}

828

138

Join BYJU'S Learning Program