If the volume of a sphere is 4851cm3, then its surface area is
A
1286cm2
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B
1386cm2
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C
1486cm2
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D
1390cm2
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Solution
The correct option is D1386cm2 The volume of the sphere =4851cm3 4πr33=4851 r3=92618 r=212cm Therefore, the surface area is =4πr2 =4×227×21×214 =1386cm2 Hence, this is the answer.