If the volume of the parallelopiped with coterminal of edges ^i+a^j+^k, ^j+a^k,a^i+^k,is minimum,then a=
A
3
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B
1√3
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C
13
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D
√3
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Solution
The correct option is C1√3 Volume of a parallelopiped=→a.(→b×→c) =⎡⎢⎣1a101aa01⎤⎥⎦ ⇒f(a)=1+a3−a(on evaluation) ⇒f′(a)=3a2−1 ⇒f′(a)=0 for a=±1√3 ⇒f′′(a)=6a=6×1√3=6√3>0 ∴f(a) is minimum for a=1√3