If the volume of the vessel in which the reaction 2NO+O2⟶2NO2 is occurring is diminished to 1/3rd of its initial volume. The rate of the reaction will be increased by:
A
3 times
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B
9 times
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C
27 times
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D
36 times
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Solution
The correct option is C 27 times
As we know that, rate of reaction is directly proportional to concentration of reactant and inversely proportional to the volume of vessel.
ie, rate ∝nV
For a given reaction,
2NO(g)+O2(g)⇌2NO2(g)
Rate of reaction =k[NO]2[O2]
If the volume of the vessel is reduced by 13rd of its initial value, then the concentration of reactant is increased by 3 times.
Rate of reaction =k(3[NO])2(3[O2])=27k[NO]2[O2]
Hence, the rate of reaction will be increased by 27 times.