If the water molecules in 1-0 g of water were distributes uniformly over the surface of earth- If there are 6-5-10-xsuch molecules would there be in 1-0 cm2 of earth-s surface - then what is the value of x-

Number of water molecules in one gram of water is #160; N= 1 18 N _ A = 6.022X 10 ^ 23 18 =3.35X 10 ^ 22 Distributing them evenly over the surface of ...

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Standard XII

Chemistry

Gay Lussac's Law, Avagadro's Law

If the water ...

Question

If the water molecules in 1.0 g of water were distributes uniformly over the surface of earth, If there are $6.5 \times 10^{- x}$ such molecules would there be in $1.0 c m^{2}$ of earth's surface , then what is the value of x?

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Solution

Number of water molecules in one gram of water is

$N = \frac{1}{18} N_{A} = \frac{6.022 X 10^{23}}{18} = 3.35 X 10^{22}$

Distributing them evenly over the surface of earth (R=6400km) gives areal density

$ρ = \frac{N}{A} = \frac{N}{4 π R^{2}} = \frac{3.35 X 10^{22}}{4 (3.142) (640000000^{2})} = 6500$

Thus, molecules in unit area are,

$d N = ρ (1 {c m}^{2}) = 6.5 X 10^{3}$

Answer is $6.5 X 10^{3}$

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If the water molecules in 1.0 g of water were distributes uniformly over the surface of earth, If there are 6.5×10−xsuch molecules would there be in 1.0cm2 of earth's surface , then what is the value of x?

Number of water molecules in one gram of water is N=118NA=6.022X102318=3.35X1022Distributing them evenly over the surface of earth (R=6400km) gives areal densityρ=NA=N4πR2=3.35X10224(3.142)(6400000002)=6500Thus, molecules in unit area are,dN=ρ(1cm2)=6.5X103Answer is 6.5X103

If the water molecules in 1.0 g of water were distributes uniformly over the surface of earth, If there are $6.5 \times 10^{- x}$ such molecules would there be in $1.0 c m^{2}$ of earth's surface , then what is the value of x?