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Question

If the wave number of 1st line of Balmer series of hydrogen atom is ‘x’ then the wave number of 1st line of Lyman series of He+ ion will be

A
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C
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Solution

The correct option is C
¯v=Rz2[1n211n22]X=R[122132]5R36
R=36x5
¯v1=R22[1122]=3R
Substituting R, we get =3×36x5=108x5

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