If the weight of 5.6 litres of a gas at N.T.P. is 11 gram. The gas may be :
A
PH3
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B
COCl2
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C
NO
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D
N2O
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Solution
The correct option is DN2O 1 mole of a gas at N.T.P occupies 22.4 L. Its weight is M which is equal to its molecular weight. 5.6 L of a gas at N.T.P weighs 11 g.
Thus 5.622.4=11M.
Hence, the molecular weight is 44 g/mol.
The gas is N2O as its molecular weight is 44 g/mol.