Question

If the weight of 5.6 litres of a gas at NTP is 11 gram. The gas may be:

• A. $P{H}_3$
• B. $COC{l}_2$
• C. $NO$
• D. $N_{2}O$

Answer 1

The correct option is D $N_{2}O$

Volume occupied by 1 mole of gas = 22.4 litres.

Moles of gas$=\frac{5.6}{22.4}=0.25$

Since, 0.25 moles weigh 11 gram, 1 mole will weigh 44 grams.

Therefore, we need a gas whose molar mass is 44 grams.

Hence, $N_{2}O$