If the weight of $81$ books is $9 k g$ , then:
The weight of $100$ such books is _____ $k g$

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Solution

Given that,
Weight of $81$ books $=$ $9 k g$
By unitary method,
Divide both side by $81$
Weight of $1$ book $=$ $\frac{9}{81} k g = \frac{1}{9} k g$
Multiply both side by $100$
Weight of $100$ books $=$ $100 \times \frac{1}{9} k g = 11.1 k g$
Hence, The weight of $100$ such books is $11.1 k g$

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