If the weight of dry raisins is W₁ and that of soaked raisins is W₂ ,then the correct equation for calculating the percentage of water absorbed by raisins will be :

(1) W₁-W₂

(2) W₂-W₁

(3) $\frac{W_{2} - W_{1}}{W_{1}} \times 100$

(4) $\frac{W_{1} - W_{2}}{W_{2}} \times 100$

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Solution

The correct equation for calculating the percentage of water absorbed by raisins will be

$\frac{W_{2} - W_{1}}{W_{1}} \times 100$

where, W₁ = Initial weight of raisins
W₂ = Final weight of raisins

Hence, the correct answer is option 3.

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(1)

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If the weight of dry raisins is W1 and that of soaked raisins is W2 ,then the correct equation for calculating the percentage of water absorbed by raisins will be : (1) W1-W2 (2) W2-W1 (3) W2-W1W1×100 (4) W1-W2W2×100

The correct equation for calculating the percentage of water absorbed by raisins will be W2-W1W1×100 where, W1 = Initial weight of raisins W2 = Final weight of raisins Hence, the correct answer is option 3.

If the weight of dry raisins is W₁ and that of soaked raisins is W₂ ,then the correct equation for calculating the percentage of water absorbed by raisins will be :

(1) W₁-W₂

(2) W₂-W₁

(3) $\frac{W_{2} - W_{1}}{W_{1}} \times 100$

(4) $\frac{W_{1} - W_{2}}{W_{2}} \times 100$

The correct equation for calculating the percentage of water absorbed by raisins will be

$\frac{W_{2} - W_{1}}{W_{1}} \times 100$

where, W₁ = Initial weight of raisins
W₂ = Final weight of raisins

Hence, the correct answer is option 3.