Question

If the weight of metal chloride is x gram containing y gram of metal, the equivalent weight of metal will be:

• A. $E=\frac{x}{y}\times 35.5$
• B. $E=\frac{8(y-x)}{x}$
• C. $E=\frac{y}{x-y}\times 35.5$
• D. $E=\frac{8(x-y)}{y}$

Answer 1

The correct option is C $E=\frac{y}{x-y}\times 35.5$

Solution:- (C) $E=\frac{y}{(x-y)}\times 35.5$

Weight of metal $=yg$

Weight of metal chloride $=xg$

$\therefore$ Weight of chlorine $=(x-y)g$

Molecular weight of chlorine $=35.5g$

As we know that,

$\text{No. of moles}=\frac{\text{weight}}{\text{mol. wt.}}$

$\therefore$ No. of moles of chlorine $=\frac{(x-y)}{35.5}$

Let E be the equivalent weight of metal.

Equivalent of chlorine $=35.5g$

As we know that $\text{gm eq.}=\frac{\text{wt.}}{\text{eq. wt.}}$

$\therefore {\left(\text{gm eq.}\right)}_{Cl}={\left(\text{gm eq.}\right)}_{Metal}$

$\Rightarrow \frac{(x-y)}{35.5}=\frac{y}{E}$

$\Rightarrow E=\frac{y}{(x-y)}\times 35.5$

Hence, option $C$ is correct.