If the weights of gold, water and copper are in the following proportion 19 $:$ 1 $:$ 9, then in what ratio should these metals be mixed so that the mixture may be 15 times as heavy as water?

3:2

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2:3

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4:5

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5:4

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None of these

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Solution

The correct option is A
3:2

$\therefore$ Gold : Copper = 6 $:$ 4 = 3 $:$ 2

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If the weights of gold, water and copper are in the following proportion 19:1:9, then in what ratio should these metals be mixed so that the mixture may be 15 times as heavy as water?

The correct option is A 3:2 Gold : Copper = 6:4 = 3:2

If the weights of gold, water and copper are in the following proportion 19 $:$ 1 $:$ 9, then in what ratio should these metals be mixed so that the mixture may be 15 times as heavy as water?

The correct option is A
3:2

$\therefore$ Gold : Copper = 6 $:$ 4 = 3 $:$ 2