If the wheel with 16 teeth revolves at $1000 r p m$ , how fast does the driven sprocket revolve?

333 r p m

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303 r p m

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3330 r p m

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3333 r p m

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Solution

The correct option is A $333 r p m$
First, we have to calculate the $V R$ of syste m
$V R = \frac{16 t}{48 t} = 1 : 3$
Now for the $r p m$ with which driven sprocket revolve is givven by
$r p m = 1000 * V R = 1000 * 1 / 3 = 333 r p m$

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If the wheel with 16 teeth revolves at 1000rpm, how fast does the driven sprocket revolve?

The correct option is A 333rpmFirst, we have to calculate the VRof syste m VR=16t48t=1:3Now for the rpm with which driven sprocket revolve is givven by rpm=1000∗VR=1000∗1/3=333rpm

If the wheel with 16 teeth revolves at $1000 r p m$ , how fast does the driven sprocket revolve?

The correct option is A $333 r p m$
First, we have to calculate the $V R$ of syste m
$V R = \frac{16 t}{48 t} = 1 : 3$
Now for the $r p m$ with which driven sprocket revolve is givven by
$r p m = 1000 * V R = 1000 * 1 / 3 = 333 r p m$