Question

If the work done by a force in moving an object through a distance of 20 cm is 24.2 J, what is the magnitude of the force?

Answer 1

Work done by a force is defined as the product of the force and the displacement.

Work done, $W=F\times s$

Work done = 24.2 J

Displacement = 20 cm = 0.2 m

$F=\frac{W}{s}=\frac{24.2\mathrm{J}}{0.2\mathrm{m}}=121\mathrm{N}$

Hence, the magnitude of the force is 121 N.