If the work done by a force in moving an object through a distance of $20 m$ is $24.5 J$ , find the magnitude of force.

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Solution

Step: Data provided,
$D i s \tan c e = 20 m W o r k d o n e = 24.5 J$
Step 2: Formula used,
$W o r k = F o r c e \times D i s p l a c e m e n t$
Step 3: Calculation,
$W o r k = F o r c e \times D i s p l a c e m e n t F o r c e = \frac{W o r k}{D i s p l a c e m e n t} = \frac{24.5 J}{20 m} = 1.225 N$
Hence, the required force is $1.225 N$

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