Question

If the work done in moving a charge of $2\text{mC}$ across two points having potential difference $V$ is $24\text{J}$, then the value of $V$ is

• A. $12\text{V}$
• B. $12\times {10}^2\text{V}$
• C. $12\times {10}^3\text{V}$
• D. $12\times {10}^4\text{V}$

Answer 1

The correct option is C $12\times {10}^3\text{V}$

Charge, $q=2\text{mC}=2\times {10}^{–3}\text{C}$
Work done in moving charge through potential difference $V,W=24\text{J}$
Now, $W=qV$
$\Rightarrow V=\frac{W}{q}=\frac{24}{2\times {10}^{-3}}=12\times {10}^3\text{V}$
Hence, the correct answer is option (c).