If the work done to transfer $10 C$ of charge slowly between two bodies A and B is $10 J$ , then find the potential difference maintained between them.

20 V

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100 V

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1 V

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0 V

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Solution

The correct option is C 1 V
Given:
Charge, $Q = 10 C$
Work done, $W = 10 J$

Let the potential difference be $V$ . Using the formula for potential difference,
$V = \frac{W}{Q}$
$V = \frac{10 J}{10 C} = 1 V$

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