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Question
If the work function for a certain metal is 3.2×10−19J and it is illuminated with light of frequency 8×1014 Hz . The maximum kinetic energy of the photoelectrons would be: (h=6.63×10−34 Js)
If the work function for a certain metal is 3.2×10−19J and it is illuminated with light of frequency 8×1014 Hz . The maximum kinetic energy of the photoelectrons would be: (h=6.63×10−34 Js)
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Solution
The correct option is B 2.1×10−19J
K.E.max=incident energy - work function
=hγ−3.2×10−19
=6.63×10−34×8×1014−3.2×10−19
=5.3×10−19−3.2×10−19
=2.1×10−19J.
K.E.max=incident energy - work function
=hγ−3.2×10−19
=6.63×10−34×8×1014−3.2×10−19
=5.3×10−19−3.2×10−19
=2.1×10−19J.
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