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Byju's Answer
Standard IX
Mathematics
(x±a)(x±b) = x²±(a+b)x+ab.
If the zeroes...
Question
If the zeroes of the polynomial
5
x
2
−
7
x
+
k
are reciprocal of each other, then find the value of
k
.
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Solution
Zeros of the polynomial are the roots of this quadratc equation
5
x
2
−
7
x
+
k
=
0
Given that the roots re reciprocal of each other. Hence product of roots will be
1
From the given equation we can see that product of the roots
=
k
5
⇒
k
5
=
1
⇒
k
=
5
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