wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the zeroes of the quadratic polynomial x2+a+1x+b. are 2 and -3, then

(a) a = -7, b = -1 (b) a = 5 , b = -1 (c) a =2 , b = -6 (d) a = 0 , b = -6

Open in App
Solution

The given quadratic equation is x2+a+1x+b=0.
Since the zeroes of the given equation are 2 and –3.
So,
α=2 and β=-3
Now,
Sum of zeroes=-Coefficient of xCoefficient of x22+-3=-a+11-1=-a-1a=0
Product of zeroes=Constant termCoefficient of x22×-3=b1b=-6
So, a = 0 and b = −6

Hence, the correct answer is option D.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon